1. # Project Euler: Problem 10

Published: Wed 06 July 2011

In blog.

Thank you for your patience as you all (I'm sure) anxiously await my next posting.

Not only has it been a really long time since I posted something technical, it's also been a really long time since I posted a Project Euler solution. On that note, let's ...

2. # The Devil is in the Details

This story happened a while ago, but because I've been so busy I haven't really had the time to put it on (electronic) paper. While hanging out on Twitter I saw a message asking why one version of Haskell code was preferred over another. So I followed the ...

3. # Project Euler: Problem 9

Published: Thu 06 January 2011

In blog.

Happy New Year Ladies(?) and Geeks

Trying to get the year off to a good start, I'm posting up my solution for the ninth Project Euler problem. I'm not going to spend a lot of time talking about it, because the solution is a pretty easy one. Here ...

4. # Project Euler: Problem 8

Published: Wed 03 November 2010

In blog.

The website has problem eight stated as such,

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22``` ```Find the greatest product of five consecutive digits in the 1000-digit number. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 ...```

5. # Project Euler: Problem 6

Published: Tue 24 August 2010

In blog.

After a nice vacation, the obsession continues.

 ``` 1 2 3 4 5 6 7 8 9 10 11 12``` ```The sum of the squares of the first ten natural numbers is,` 12 + 22 + ... + 102 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10 ...```

6. # Project Euler: Problem 5

Published: Thu 29 July 2010

In blog.

It's that time again. ;)

 ```1 2 3``` ```2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to ...```

7. # Project Euler: Problem 4

Published: Thu 08 July 2010

In blog.

If you been following me the last three times I've done this, then you really don't need any introductions.

Problem four is as follows:

 ```1 2 3 4 5``` ```A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers ...```

8. # Project Euler: Problem 3

Published: Fri 02 July 2010

In blog.

OK, next installment of this. :)

The problem is stated as such:

 ```1 2 3``` ```The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? ```

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 ...```

9. # Project Euler, Problem 2

Published: Thu 24 June 2010

In blog.

I've got problem #2 in the bag.

Problem #2 goes like this:

 ```1 2 3 4 5 6 7``` ```Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3 ...```

10. # Project Euler: Problem 1

Published: Fri 18 June 2010

In blog.

So I'll admit it, I'm more than acceptably late to this party. OJ started working on these problems years ago, while I was still coding away on other stuff at school. Now that I'm not in school and needing a challenge I'm doing the best I ...